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13201301201 = 111200118291
BaseRepresentation
bin11000100101101101…
…11101111011010001
31021002000120120210112
430102312331323101
5204014013114301
610021541411105
7645066131414
oct142266757321
937060516715
1013201301201
115664876a90
122685109a95
131324cc333a
148d33a9b7b
15523e669bb
hex312dbded1

13201301201 has 4 divisors (see below), whose sum is σ = 14401419504. Its totient is φ = 12001182900.

The previous prime is 13201301173. The next prime is 13201301209. The reversal of 13201301201 is 10210310231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13201301201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13201301209) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600059135 + ... + 600059156.

It is an arithmetic number, because the mean of its divisors is an integer number (3600354876).

Almost surely, 213201301201 is an apocalyptic number.

13201301201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13201301201 is a deficient number, since it is larger than the sum of its proper divisors (1200118303).

13201301201 is a wasteful number, since it uses less digits than its factorization.

13201301201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1200118302.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 13201301201 its reverse (10210310231), we get a palindrome (23411611432).

The spelling of 13201301201 in words is "thirteen billion, two hundred one million, three hundred one thousand, two hundred one".

Divisors: 1 11 1200118291 13201301201