Base | Representation |
---|---|
bin | 1100000000011010101110… |
… | …0000111111011110011001 |
3 | 1201202000220010122102022211 |
4 | 3000012223200333132121 |
5 | 3212242241341200040 |
6 | 44024333220315121 |
7 | 2531522550666256 |
oct | 300065340773631 |
9 | 51660803572284 |
10 | 13201312053145 |
11 | 422a710550937 |
12 | 1592604842aa1 |
13 | 749b55a727a8 |
14 | 338d3848442d |
15 | 17d5e2dcc8ea |
hex | c01ab83f799 |
13201312053145 has 16 divisors (see below), whose sum is σ = 16391684232000. Its totient is φ = 10194480845248.
The previous prime is 13201312053121. The next prime is 13201312053173. The reversal of 13201312053145 is 54135021310231.
13201312053145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13201312053145 - 211 = 13201312051097 is a prime.
It is a super-2 number, since 2×132013120531452 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10070815 + ... + 11305924.
It is an arithmetic number, because the mean of its divisors is an integer number (1024480264500).
Almost surely, 213201312053145 is an apocalyptic number.
It is an amenable number.
13201312053145 is a deficient number, since it is larger than the sum of its proper divisors (3190372178855).
13201312053145 is a wasteful number, since it uses less digits than its factorization.
13201312053145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21381032.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 13201312053145 its reverse (54135021310231), we get a palindrome (67336333363376).
The spelling of 13201312053145 in words is "thirteen trillion, two hundred one billion, three hundred twelve million, fifty-three thousand, one hundred forty-five".
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