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13201402001003 = 38333444143491
BaseRepresentation
bin1100000000011011000011…
…1000000111011001101011
31201202001010101220020120222
43000012300320013121223
53212242432403013003
644024350152240255
72531525022354026
oct300066070073153
951661111806528
1013201402001003
11422a7572a7007
12159262a9a008b
13749b6b5a6a88
14338d463ba1bd
1517d5eac48c38
hexc01b0e0766b

13201402001003 has 4 divisors (see below), whose sum is σ = 13204846148328. Its totient is φ = 13197957853680.

The previous prime is 13201402000993. The next prime is 13201402001059. The reversal of 13201402001003 is 30010020410231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13201402001003 - 28 = 13201402000747 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13201402001063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1722067913 + ... + 1722075578.

It is an arithmetic number, because the mean of its divisors is an integer number (3301211537082).

Almost surely, 213201402001003 is an apocalyptic number.

13201402001003 is a deficient number, since it is larger than the sum of its proper divisors (3444147325).

13201402001003 is an equidigital number, since it uses as much as digits as its factorization.

13201402001003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3444147324.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13201402001003 its reverse (30010020410231), we get a palindrome (43211422411234).

The spelling of 13201402001003 in words is "thirteen trillion, two hundred one billion, four hundred two million, one thousand, three".

Divisors: 1 3833 3444143491 13201402001003