Base | Representation |
---|---|
bin | 11110000001000011101111… |
… | …011100110010110010001011 |
3 | 122022102102112211220211121211 |
4 | 132001003233130302302023 |
5 | 114300404420310100043 |
6 | 1144434242143113551 |
7 | 36543464155165003 |
oct | 3601035734626213 |
9 | 568372484824554 |
10 | 132014132112523 |
11 | 39077973a81351 |
12 | 129812818a28b7 |
13 | 5887b579035cb |
14 | 24857378b5003 |
15 | 103decd0a3a9d |
hex | 7810ef732c8b |
132014132112523 has 4 divisors (see below), whose sum is σ = 132014586648448. Its totient is φ = 132013677576600.
The previous prime is 132014132112503. The next prime is 132014132112613. The reversal of 132014132112523 is 325211231410231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132014132112523 - 225 = 132014098558091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132014132112503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226832028 + ... + 227413273.
It is an arithmetic number, because the mean of its divisors is an integer number (33003646662112).
Almost surely, 2132014132112523 is an apocalyptic number.
132014132112523 is a deficient number, since it is larger than the sum of its proper divisors (454535925).
132014132112523 is an equidigital number, since it uses as much as digits as its factorization.
132014132112523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 454535924.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 132014132112523 its reverse (325211231410231), we get a palindrome (457225363522754).
The spelling of 132014132112523 in words is "one hundred thirty-two trillion, fourteen billion, one hundred thirty-two million, one hundred twelve thousand, five hundred twenty-three".
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