Base | Representation |
---|---|
bin | 1100000000011011000111… |
… | …1101101111110011000011 |
3 | 1201202001011200020121112211 |
4 | 3000012301331233303003 |
5 | 3212243002041120103 |
6 | 44024352043402551 |
7 | 2531525333456653 |
oct | 300066175576303 |
9 | 51661150217484 |
10 | 13201420254403 |
11 | 422a766634067 |
12 | 1592634b23457 |
13 | 749b722c81c4 |
14 | 338d489ac363 |
15 | 17d5ec65236d |
hex | c01b1f6fcc3 |
13201420254403 has 16 divisors (see below), whose sum is σ = 13932093427200. Its totient is φ = 12474351470880.
The previous prime is 13201420254389. The next prime is 13201420254419. The reversal of 13201420254403 is 30445202410231.
It is a cyclic number.
It is not a de Polignac number, because 13201420254403 - 233 = 13192830319811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13201426254403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26001193 + ... + 26504053.
It is an arithmetic number, because the mean of its divisors is an integer number (870755839200).
Almost surely, 213201420254403 is an apocalyptic number.
13201420254403 is a deficient number, since it is larger than the sum of its proper divisors (730673172797).
13201420254403 is a wasteful number, since it uses less digits than its factorization.
13201420254403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 506442.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 13201420254403 its reverse (30445202410231), we get a palindrome (43646622664634).
The spelling of 13201420254403 in words is "thirteen trillion, two hundred one billion, four hundred twenty million, two hundred fifty-four thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •