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13201420254403 = 194433119502861
BaseRepresentation
bin1100000000011011000111…
…1101101111110011000011
31201202001011200020121112211
43000012301331233303003
53212243002041120103
644024352043402551
72531525333456653
oct300066175576303
951661150217484
1013201420254403
11422a766634067
121592634b23457
13749b722c81c4
14338d489ac363
1517d5ec65236d
hexc01b1f6fcc3

13201420254403 has 16 divisors (see below), whose sum is σ = 13932093427200. Its totient is φ = 12474351470880.

The previous prime is 13201420254389. The next prime is 13201420254419. The reversal of 13201420254403 is 30445202410231.

It is a cyclic number.

It is not a de Polignac number, because 13201420254403 - 233 = 13192830319811 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13201426254403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26001193 + ... + 26504053.

It is an arithmetic number, because the mean of its divisors is an integer number (870755839200).

Almost surely, 213201420254403 is an apocalyptic number.

13201420254403 is a deficient number, since it is larger than the sum of its proper divisors (730673172797).

13201420254403 is a wasteful number, since it uses less digits than its factorization.

13201420254403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 506442.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 13201420254403 its reverse (30445202410231), we get a palindrome (43646622664634).

The spelling of 13201420254403 in words is "thirteen trillion, two hundred one billion, four hundred twenty million, two hundred fifty-four thousand, four hundred three".

Divisors: 1 19 443 3119 8417 59261 502861 1381717 9554359 26252623 222767423 1568423459 4232581037 29800045721 694811592337 13201420254403