Base | Representation |
---|---|
bin | 1100000000011011001011… |
… | …0010001100011111001011 |
3 | 1201202001012122010010122001 |
4 | 3000012302302030133023 |
5 | 3212243014101102103 |
6 | 44024353254211431 |
7 | 2531525561362342 |
oct | 300066262143713 |
9 | 51661178103561 |
10 | 13201434003403 |
11 | 422a773374978 |
12 | 1592639653b77 |
13 | 749b751002c9 |
14 | 338d4a74ab59 |
15 | 17d5ed96b01d |
hex | c01b2c8c7cb |
13201434003403 has 8 divisors (see below), whose sum is σ = 13421935292480. Its totient is φ = 12981622860360.
The previous prime is 13201434003389. The next prime is 13201434003437. The reversal of 13201434003403 is 30430043410231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-13201434003403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13201434003493) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 172497933 + ... + 172574446.
It is an arithmetic number, because the mean of its divisors is an integer number (1677741911560).
Almost surely, 213201434003403 is an apocalyptic number.
13201434003403 is a deficient number, since it is larger than the sum of its proper divisors (220501289077).
13201434003403 is an equidigital number, since it uses as much as digits as its factorization.
13201434003403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 345073017.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 13201434003403 its reverse (30430043410231), we get a palindrome (43631477413634).
The spelling of 13201434003403 in words is "thirteen trillion, two hundred one billion, four hundred thirty-four million, three thousand, four hundred three".
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