Base | Representation |
---|---|
bin | 1111101111001… |
… | …10101111101011 |
3 | 100012102011110101 |
4 | 13313212233223 |
5 | 232244022011 |
6 | 21033330231 |
7 | 3162061411 |
oct | 767465753 |
9 | 305364411 |
10 | 132017131 |
11 | 6857a474 |
12 | 38266977 |
13 | 2147395c |
14 | 137672b1 |
15 | b8cb2c1 |
hex | 7de6beb |
132017131 has 4 divisors (see below), whose sum is σ = 132047352. Its totient is φ = 131986912.
The previous prime is 132017063. The next prime is 132017167. The reversal of 132017131 is 131710231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131710231 = 1439 ⋅91529.
It is a cyclic number.
It is not a de Polignac number, because 132017131 - 223 = 123628523 is a prime.
It is a super-2 number, since 2×1320171312 = 34857045754942322, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132017099 and 132017108.
It is not an unprimeable number, because it can be changed into a prime (132017531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7165 + ... + 17758.
It is an arithmetic number, because the mean of its divisors is an integer number (33011838).
Almost surely, 2132017131 is an apocalyptic number.
132017131 is a deficient number, since it is larger than the sum of its proper divisors (30221).
132017131 is an equidigital number, since it uses as much as digits as its factorization.
132017131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30220.
The product of its (nonzero) digits is 126, while the sum is 19.
The square root of 132017131 is about 11489.8707999699. The cubic root of 132017131 is about 509.1863625138.
Adding to 132017131 its reverse (131710231), we get a palindrome (263727362).
The spelling of 132017131 in words is "one hundred thirty-two million, seventeen thousand, one hundred thirty-one".
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