Base | Representation |
---|---|
bin | 10011001101100010000… |
… | …100001000101010111011 |
3 | 11200012200000121111111222 |
4 | 103031202010020222323 |
5 | 133112232223224011 |
6 | 2450254104142255 |
7 | 164244535432244 |
oct | 23154204105273 |
9 | 4605600544458 |
10 | 1320200211131 |
11 | 46999166885a |
12 | 193a4446798b |
13 | 976571014a9 |
14 | 47c802a9ccb |
15 | 2451c53cddb |
hex | 13362108abb |
1320200211131 has 8 divisors (see below), whose sum is σ = 1331156987904. Its totient is φ = 1309252208040.
The previous prime is 1320200211079. The next prime is 1320200211157. The reversal of 1320200211131 is 1311120020231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1320200211131 - 218 = 1320199948987 is a prime.
It is a super-2 number, since 2×13202002111312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1320200231131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1891055 + ... + 2493288.
It is an arithmetic number, because the mean of its divisors is an integer number (166394623488).
Almost surely, 21320200211131 is an apocalyptic number.
1320200211131 is a deficient number, since it is larger than the sum of its proper divisors (10956776773).
1320200211131 is a wasteful number, since it uses less digits than its factorization.
1320200211131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4386841.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1320200211131 its reverse (1311120020231), we get a palindrome (2631320231362).
The spelling of 1320200211131 in words is "one trillion, three hundred twenty billion, two hundred million, two hundred eleven thousand, one hundred thirty-one".
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