Base | Representation |
---|---|
bin | 1100000000011101010111… |
… | …1101110010001100101011 |
3 | 1201202002201202202110112022 |
4 | 3000013111331302030223 |
5 | 3212300221201302021 |
6 | 44024532021135055 |
7 | 2531546316343421 |
oct | 300072575621453 |
9 | 51662652673468 |
10 | 13202024244011 |
11 | 422aa46567429 |
12 | 159278325a48b |
13 | 749c3a48c9c5 |
14 | 338da4cb3111 |
15 | 17d6356ac1ab |
hex | c01d5f7232b |
13202024244011 has 12 divisors (see below), whose sum is σ = 13470454769616. Its totient is φ = 12938717193120.
The previous prime is 13202024243983. The next prime is 13202024244037. The reversal of 13202024244011 is 11044242020231.
13202024244011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13202024244011 - 210 = 13202024242987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13202024244061) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5373575 + ... + 7435008.
It is an arithmetic number, because the mean of its divisors is an integer number (1122537897468).
Almost surely, 213202024244011 is an apocalyptic number.
13202024244011 is a deficient number, since it is larger than the sum of its proper divisors (268430525605).
13202024244011 is an equidigital number, since it uses as much as digits as its factorization.
13202024244011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12808982 (or 12808921 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 26.
Adding to 13202024244011 its reverse (11044242020231), we get a palindrome (24246266264242).
The spelling of 13202024244011 in words is "thirteen trillion, two hundred two billion, twenty-four million, two hundred forty-four thousand, eleven".
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