13202051435641 has 4 divisors (see below), whose sum is σ = 13206972068752. Its totient is φ = 13197130802532.

The previous prime is 13202051435509. The next prime is 13202051435663. The reversal of 13202051435641 is 14653415020231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13202051435641 - 2²⁵ = 13202017881209 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13202051435641.

It is not an unprimeable number, because it can be changed into a prime (13202051465641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2460312531 + ... + 2460317896.

It is an arithmetic number, because the mean of its divisors is an integer number (3301743017188).

Almost surely, 2^{13202051435641} is an apocalyptic number.

It is an amenable number.

13202051435641 is a deficient number, since it is larger than the sum of its proper divisors (4920633111).

13202051435641 is an equidigital number, since it uses as much as digits as its factorization.

13202051435641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4920633110.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 13202051435641 its reverse (14653415020231), we get a palindrome (27855466455872).

The spelling of 13202051435641 in words is "thirteen trillion, two hundred two billion, fifty-one million, four hundred thirty-five thousand, six hundred forty-one".