132022113 has 4 divisors (see below), whose sum is σ = 176029488. Its totient is φ = 88014740.

The previous prime is 132022103. The next prime is 132022147. The reversal of 132022113 is 311220231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132022113 - 2⁴ = 132022097 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 132022092 and 132022101.

It is not an unprimeable number, because it can be changed into a prime (132022103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22003683 + ... + 22003688.

It is an arithmetic number, because the mean of its divisors is an integer number (44007372).

Almost surely, 2^132022113 is an apocalyptic number.

It is an amenable number.

132022113 is a deficient number, since it is larger than the sum of its proper divisors (44007375).

132022113 is an equidigital number, since it uses as much as digits as its factorization.

132022113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44007374.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 132022113 is about 11490.0875975773. The cubic root of 132022113 is about 509.1927675779.

Adding to 132022113 its reverse (311220231), we get a palindrome (443242344).

The spelling of 132022113 in words is "one hundred thirty-two million, twenty-two thousand, one hundred thirteen".