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13202413300433 = 714599112919009
BaseRepresentation
bin1100000000011110110100…
…1001111010101011010001
31201202010201212211120121102
43000013231021322223101
53212302020301103213
644025034400034145
72531562052305620
oct300075511725321
951663655746542
1013202413300433
114230126138265
121592871602955
13749c9cc6c0c6
143390008296b7
1517d65990d158
hexc01ed27aad1

13202413300433 has 8 divisors (see below), whose sum is σ = 15088576863360. Its totient is φ = 11316275867520.

The previous prime is 13202413300387. The next prime is 13202413300469. The reversal of 13202413300433 is 33400331420231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13202413300433 - 28 = 13202413300177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13202413300396 and 13202413300405.

It is not an unprimeable number, because it can be changed into a prime (13202413300493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5437568 + ... + 7481441.

It is an arithmetic number, because the mean of its divisors is an integer number (1886072107920).

Almost surely, 213202413300433 is an apocalyptic number.

It is an amenable number.

13202413300433 is a deficient number, since it is larger than the sum of its proper divisors (1886163562927).

13202413300433 is a wasteful number, since it uses less digits than its factorization.

13202413300433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13065007.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 13202413300433 its reverse (33400331420231), we get a palindrome (46602744720664).

The spelling of 13202413300433 in words is "thirteen trillion, two hundred two billion, four hundred thirteen million, three hundred thousand, four hundred thirty-three".

Divisors: 1 7 145991 1021937 12919009 90433063 1886059042919 13202413300433