1320244240331 has 8 divisors (see below), whose sum is σ = 1329727728240. Its totient is φ = 1310774351328.

The previous prime is 1320244240321. The next prime is 1320244240333. The reversal of 1320244240331 is 1330424420231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1320244240331 - 2³⁰ = 1319170498507 is a prime.

It is a super-4 number, since 4×1320244240331⁴ (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320244240294 and 1320244240303.

It is not an unprimeable number, because it can be changed into a prime (1320244240333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3204821 + ... + 3593238.

It is an arithmetic number, because the mean of its divisors is an integer number (166215966030).

Almost surely, 2^{1320244240331} is an apocalyptic number.

1320244240331 is a deficient number, since it is larger than the sum of its proper divisors (9483487909).

1320244240331 is a wasteful number, since it uses less digits than its factorization.

1320244240331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6799453.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 1320244240331 its reverse (1330424420231), we get a palindrome (2650668660562).

The spelling of 1320244240331 in words is "one trillion, three hundred twenty billion, two hundred forty-four million, two hundred forty thousand, three hundred thirty-one".