132025033434145 has 8 divisors (see below), whose sum is σ = 158567446927656. Its totient is φ = 105528422209536.

The previous prime is 132025033434143. The next prime is 132025033434157. The reversal of 132025033434145 is 541434330520231.

It can be written as a sum of positive squares in 4 ways, for example, as 61216712940321 + 70808320493824 = 7824111^2 + 8414768^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132025033434145 - 2¹ = 132025033434143 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132025033434098 and 132025033434107.

It is not an unprimeable number, because it can be changed into a prime (132025033434143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11450560882 + ... + 11450572411.

It is an arithmetic number, because the mean of its divisors is an integer number (19820930865957).

Almost surely, 2^{132025033434145} is an apocalyptic number.

It is an amenable number.

132025033434145 is a deficient number, since it is larger than the sum of its proper divisors (26542413493511).

132025033434145 is a wasteful number, since it uses less digits than its factorization.

132025033434145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22901134451.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 132025033434145 its reverse (541434330520231), we get a palindrome (673459363954376).

The spelling of 132025033434145 in words is "one hundred thirty-two trillion, twenty-five billion, thirty-three million, four hundred thirty-four thousand, one hundred forty-five".