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132025045433035 = 5135918119427147
BaseRepresentation
bin11110000001001101111001…
…111011110011101011001011
3122022110110201102020221221211
4132001031321323303223023
5114301044243112324120
61144443245113313551
736544331462654656
oct3601157173635313
9568413642227854
10132025045433035
11390815642965a7
12129834087058b7
135888ba689c501
14248609106089d
15103e41b22025a
hex781379ef3acb

132025045433035 has 8 divisors (see below), whose sum is σ = 158430179237616. Its totient is φ = 105619953201120.

The previous prime is 132025045433009. The next prime is 132025045433077. The reversal of 132025045433035 is 530334540520231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 132025045433035 - 29 = 132025045432523 is a prime.

It is a super-2 number, since 2×1320250454330352 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2917669 + ... + 16509478.

It is an arithmetic number, because the mean of its divisors is an integer number (19803772404702).

Almost surely, 2132025045433035 is an apocalyptic number.

132025045433035 is a deficient number, since it is larger than the sum of its proper divisors (26405133804581).

132025045433035 is a wasteful number, since it uses less digits than its factorization.

132025045433035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20786333.

The product of its (nonzero) digits is 648000, while the sum is 40.

Adding to 132025045433035 its reverse (530334540520231), we get a palindrome (662359585953266).

The spelling of 132025045433035 in words is "one hundred thirty-two trillion, twenty-five billion, forty-five million, four hundred thirty-three thousand, thirty-five".

Divisors: 1 5 1359181 6795905 19427147 97135735 26405009086607 132025045433035