Base | Representation |
---|---|
bin | 11110000001001101111001… |
… | …111011110011101011001011 |
3 | 122022110110201102020221221211 |
4 | 132001031321323303223023 |
5 | 114301044243112324120 |
6 | 1144443245113313551 |
7 | 36544331462654656 |
oct | 3601157173635313 |
9 | 568413642227854 |
10 | 132025045433035 |
11 | 390815642965a7 |
12 | 129834087058b7 |
13 | 5888ba689c501 |
14 | 248609106089d |
15 | 103e41b22025a |
hex | 781379ef3acb |
132025045433035 has 8 divisors (see below), whose sum is σ = 158430179237616. Its totient is φ = 105619953201120.
The previous prime is 132025045433009. The next prime is 132025045433077. The reversal of 132025045433035 is 530334540520231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132025045433035 - 29 = 132025045432523 is a prime.
It is a super-2 number, since 2×1320250454330352 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2917669 + ... + 16509478.
It is an arithmetic number, because the mean of its divisors is an integer number (19803772404702).
Almost surely, 2132025045433035 is an apocalyptic number.
132025045433035 is a deficient number, since it is larger than the sum of its proper divisors (26405133804581).
132025045433035 is a wasteful number, since it uses less digits than its factorization.
132025045433035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20786333.
The product of its (nonzero) digits is 648000, while the sum is 40.
Adding to 132025045433035 its reverse (530334540520231), we get a palindrome (662359585953266).
The spelling of 132025045433035 in words is "one hundred thirty-two trillion, twenty-five billion, forty-five million, four hundred thirty-three thousand, thirty-five".
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