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132025531241 = 139994371359
BaseRepresentation
bin111101011110101010…
…1011011101101101001
3110121210002022220010102
41322331111123231221
54130342013444431
6140352433155145
712352500333152
oct1727525335551
9417702286112
10132025531241
1150a9aa7479a
12217070bbab5
13c5b071ab26
1465664cc929
15367aabadcb
hex1ebd55bb69

132025531241 has 4 divisors (see below), whose sum is σ = 132119904000. Its totient is φ = 131931158484.

The previous prime is 132025531129. The next prime is 132025531289. The reversal of 132025531241 is 142135520231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 142135520231 = 903591573009.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132025531241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132025539241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47184281 + ... + 47187078.

It is an arithmetic number, because the mean of its divisors is an integer number (33029976000).

Almost surely, 2132025531241 is an apocalyptic number.

It is an amenable number.

132025531241 is a deficient number, since it is larger than the sum of its proper divisors (94372759).

132025531241 is an equidigital number, since it uses as much as digits as its factorization.

132025531241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94372758.

The product of its (nonzero) digits is 7200, while the sum is 29.

The spelling of 132025531241 in words is "one hundred thirty-two billion, twenty-five million, five hundred thirty-one thousand, two hundred forty-one".

Divisors: 1 1399 94371359 132025531241