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132031131121 = 156784257263
BaseRepresentation
bin111101011110110101…
…0110010110111110001
3110121210110212101201101
41322331222302313301
54130344432143441
6140353153204401
712352566045301
oct1727552626761
9417713771641
10132031131121
1150aa3149a9a
1221708b60701
13c5b192b976
146567149601
15367b325231
hex1ebdab2df1

132031131121 has 4 divisors (see below), whose sum is σ = 132115389952. Its totient is φ = 131946872292.

The previous prime is 132031131107. The next prime is 132031131151. The reversal of 132031131121 is 121131130231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132031131121 - 27 = 132031130993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132031131151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42127065 + ... + 42130198.

It is an arithmetic number, because the mean of its divisors is an integer number (33028847488).

Almost surely, 2132031131121 is an apocalyptic number.

It is an amenable number.

132031131121 is a deficient number, since it is larger than the sum of its proper divisors (84258831).

132031131121 is an equidigital number, since it uses as much as digits as its factorization.

132031131121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84258830.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 132031131121 its reverse (121131130231), we get a palindrome (253162261352).

The spelling of 132031131121 in words is "one hundred thirty-two billion, thirty-one million, one hundred thirty-one thousand, one hundred twenty-one".

Divisors: 1 1567 84257263 132031131121