Base | Representation |
---|---|
bin | 10011001101101000101… |
… | …111000010011100101011 |
3 | 11200012221211012010011210 |
4 | 103031220233002130223 |
5 | 133112444400334011 |
6 | 2450313142524203 |
7 | 164250364600413 |
oct | 23155057023453 |
9 | 4605854163153 |
10 | 1320312121131 |
11 | 469a39854463 |
12 | 193a75a36663 |
13 | 97674355023 |
14 | 47c910bb643 |
15 | 245272966a6 |
hex | 13368bc272b |
1320312121131 has 16 divisors (see below), whose sum is σ = 1763204436000. Its totient is φ = 878815004928.
The previous prime is 1320312121129. The next prime is 1320312121151. The reversal of 1320312121131 is 1311212130231.
It is not a de Polignac number, because 1320312121131 - 21 = 1320312121129 is a prime.
It is a super-2 number, since 2×13203121211312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1320312121098 and 1320312121107.
It is not an unprimeable number, because it can be changed into a prime (1320312121111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4894405 + ... + 5157113.
It is an arithmetic number, because the mean of its divisors is an integer number (110200277250).
Almost surely, 21320312121131 is an apocalyptic number.
1320312121131 is a deficient number, since it is larger than the sum of its proper divisors (442892314869).
1320312121131 is a wasteful number, since it uses less digits than its factorization.
1320312121131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 265358.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1320312121131 its reverse (1311212130231), we get a palindrome (2631524251362).
The spelling of 1320312121131 in words is "one trillion, three hundred twenty billion, three hundred twelve million, one hundred twenty-one thousand, one hundred thirty-one".
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