Base | Representation |
---|---|
bin | 10011001101101000110… |
… | …111101111111000111011 |
3 | 11200012221222111010020201 |
4 | 103031220313233320323 |
5 | 133113000441420121 |
6 | 2450313303503031 |
7 | 164250423160252 |
oct | 23155067577073 |
9 | 4605858433221 |
10 | 1320314404411 |
11 | 469a40073972 |
12 | 193a76757a77 |
13 | 97674974392 |
14 | 47c91513799 |
15 | 24527597e91 |
hex | 13368defe3b |
1320314404411 has 4 divisors (see below), whose sum is σ = 1323911991712. Its totient is φ = 1316716817112.
The previous prime is 1320314404307. The next prime is 1320314404427. The reversal of 1320314404411 is 1144044130231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1320314404411 - 215 = 1320314371643 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1320314404411.
It is not an unprimeable number, because it can be changed into a prime (1320314404481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1798793100 + ... + 1798793833.
It is an arithmetic number, because the mean of its divisors is an integer number (330977997928).
Almost surely, 21320314404411 is an apocalyptic number.
1320314404411 is a deficient number, since it is larger than the sum of its proper divisors (3597587301).
1320314404411 is an equidigital number, since it uses as much as digits as its factorization.
1320314404411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3597587300.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1320314404411 its reverse (1144044130231), we get a palindrome (2464358534642).
The spelling of 1320314404411 in words is "one trillion, three hundred twenty billion, three hundred fourteen million, four hundred four thousand, four hundred eleven".
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