132031550444441 has 4 divisors (see below), whose sum is σ = 132031675488384. Its totient is φ = 132031425400500.

The previous prime is 132031550444413. The next prime is 132031550444477. The reversal of 132031550444441 is 144444055130231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132031550444441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132031550444411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60924545 + ... + 63054446.

It is an arithmetic number, because the mean of its divisors is an integer number (33007918872096).

Almost surely, 2^{132031550444441} is an apocalyptic number.

It is an amenable number.

132031550444441 is a deficient number, since it is larger than the sum of its proper divisors (125043943).

132031550444441 is a wasteful number, since it uses less digits than its factorization.

132031550444441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125043942.

The product of its (nonzero) digits is 460800, while the sum is 41.

The spelling of 132031550444441 in words is "one hundred thirty-two trillion, thirty-one billion, five hundred fifty million, four hundred forty-four thousand, four hundred forty-one".