Base | Representation |
---|---|
bin | 111101011110111011… |
… | …0001000101011101001 |
3 | 110121210200110102210112 |
4 | 1322331312020223221 |
5 | 4130401212312131 |
6 | 140353341024105 |
7 | 12352633236560 |
oct | 1727566105351 |
9 | 417720412715 |
10 | 132034104041 |
11 | 50aa489a654 |
12 | 21709b55035 |
13 | c5b242cba8 |
14 | 65676c0bd7 |
15 | 367b71102b |
hex | 1ebdd88ae9 |
132034104041 has 16 divisors (see below), whose sum is σ = 154800444288. Its totient is φ = 110251843200.
The previous prime is 132034104029. The next prime is 132034104053. The reversal of 132034104041 is 140401430231.
It is an interprime number because it is at equal distance from previous prime (132034104029) and next prime (132034104053).
It is a cyclic number.
It is not a de Polignac number, because 132034104041 - 210 = 132034103017 is a prime.
It is a super-2 number, since 2×1320341040412 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132034103998 and 132034104016.
It is not an unprimeable number, because it can be changed into a prime (132034104001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 134570 + ... + 531203.
It is an arithmetic number, because the mean of its divisors is an integer number (9675027768).
Almost surely, 2132034104041 is an apocalyptic number.
It is an amenable number.
132034104041 is a deficient number, since it is larger than the sum of its proper divisors (22766340247).
132034104041 is an equidigital number, since it uses as much as digits as its factorization.
132034104041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 666512.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 132034104041 its reverse (140401430231), we get a palindrome (272435534272).
The spelling of 132034104041 in words is "one hundred thirty-two billion, thirty-four million, one hundred four thousand, forty-one".
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