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1320343953843 = 3440114651281
BaseRepresentation
bin10011001101101010101…
…000011110000110110011
311200020001001002101110010
4103031222220132012303
5133113031023010333
62450320241110003
7164251232301225
oct23155250360663
94606031071403
101320343953843
11469a55816892
12193a84628303
139767ab1c255
1447c95406415
1524529e83563
hex1336aa1e1b3

1320343953843 has 4 divisors (see below), whose sum is σ = 1760458605128. Its totient is φ = 880229302560.

The previous prime is 1320343953827. The next prime is 1320343953913. The reversal of 1320343953843 is 3483593430231.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1320343953843 - 24 = 1320343953827 is a prime.

It is a super-2 number, since 2×13203439538432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320343953792 and 1320343953801.

It is not an unprimeable number, because it can be changed into a prime (1320343953823) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220057325638 + ... + 220057325643.

It is an arithmetic number, because the mean of its divisors is an integer number (440114651282).

Almost surely, 21320343953843 is an apocalyptic number.

1320343953843 is a deficient number, since it is larger than the sum of its proper divisors (440114651285).

1320343953843 is an equidigital number, since it uses as much as digits as its factorization.

1320343953843 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440114651284.

The product of its (nonzero) digits is 2799360, while the sum is 48.

The spelling of 1320343953843 in words is "one trillion, three hundred twenty billion, three hundred forty-three million, nine hundred fifty-three thousand, eight hundred forty-three".

Divisors: 1 3 440114651281 1320343953843