Base | Representation |
---|---|
bin | 1100000000100011000001… |
… | …1001010111010111000011 |
3 | 1201202020122111121011121021 |
4 | 3000020300121113113003 |
5 | 3212311323101023210 |
6 | 44025342335410311 |
7 | 2531632031222410 |
oct | 300106031272703 |
9 | 51666574534537 |
10 | 13203541423555 |
11 | 4230654a1091a |
12 | 1592b27383997 |
13 | 74a11c8b8692 |
14 | 3390aa5a9107 |
15 | 17d6c399bbda |
hex | c02306575c3 |
13203541423555 has 16 divisors (see below), whose sum is σ = 18107928020160. Its totient is φ = 9053749942272.
The previous prime is 13203541423531. The next prime is 13203541423601. The reversal of 13203541423555 is 55532414530231.
It is a de Polignac number, because none of the positive numbers 2k-13203541423555 is a prime.
It is a super-2 number, since 2×132035414235552 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 832251 + ... + 5205739.
It is an arithmetic number, because the mean of its divisors is an integer number (1131745501260).
Almost surely, 213203541423555 is an apocalyptic number.
13203541423555 is a deficient number, since it is larger than the sum of its proper divisors (4904386596605).
13203541423555 is an equidigital number, since it uses as much as digits as its factorization.
13203541423555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4459758.
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 13203541423555 its reverse (55532414530231), we get a palindrome (68735955953786).
The spelling of 13203541423555 in words is "thirteen trillion, two hundred three billion, five hundred forty-one million, four hundred twenty-three thousand, five hundred fifty-five".
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