Base | Representation |
---|---|
bin | 111101011111001000… |
… | …1001101001001110001 |
3 | 110121211011210221221202 |
4 | 1322332101031021301 |
5 | 4130410021401431 |
6 | 140354153100545 |
7 | 12353050453316 |
oct | 1727621151161 |
9 | 417734727852 |
10 | 132041200241 |
11 | 50aa88a7085 |
12 | 217103b7755 |
13 | c5b3a45b22 |
14 | 656860ad0d |
15 | 367c1638cb |
hex | 1ebe44d271 |
132041200241 has 8 divisors (see below), whose sum is σ = 135126614304. Its totient is φ = 128956453920.
The previous prime is 132041200237. The next prime is 132041200289. The reversal of 132041200241 is 142002140231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132041200241 - 22 = 132041200237 is a prime.
It is a super-2 number, since 2×1320412002412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132041200211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 244901 + ... + 569261.
It is an arithmetic number, because the mean of its divisors is an integer number (16890826788).
Almost surely, 2132041200241 is an apocalyptic number.
It is an amenable number.
132041200241 is a deficient number, since it is larger than the sum of its proper divisors (3085414063).
132041200241 is an equidigital number, since it uses as much as digits as its factorization.
132041200241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 333871.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 132041200241 its reverse (142002140231), we get a palindrome (274043340472).
The spelling of 132041200241 in words is "one hundred thirty-two billion, forty-one million, two hundred thousand, two hundred forty-one".
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