Base | Representation |
---|---|
bin | 1100000000100110000000… |
… | …1011011110001010101001 |
3 | 1201202022201101001221012001 |
4 | 3000021200023132022221 |
5 | 3212314443312302120 |
6 | 44025554054051001 |
7 | 2531660634240043 |
oct | 300114013361251 |
9 | 51668641057161 |
10 | 13204343087785 |
11 | 4230a26489043 |
12 | 159310b949a61 |
13 | 74a219a01c05 |
14 | 339144c48a93 |
15 | 17d71e051e0a |
hex | c02602de2a9 |
13204343087785 has 4 divisors (see below), whose sum is σ = 15845211705348. Its totient is φ = 10563474470224.
The previous prime is 13204343087737. The next prime is 13204343087843. The reversal of 13204343087785 is 58778034340231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2946344786064 + 10257998301721 = 1716492^2 + 3202811^2 .
It is a cyclic number.
It is not a de Polignac number, because 13204343087785 - 211 = 13204343085737 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320434308774 + ... + 1320434308783.
It is an arithmetic number, because the mean of its divisors is an integer number (3961302926337).
Almost surely, 213204343087785 is an apocalyptic number.
It is an amenable number.
13204343087785 is a deficient number, since it is larger than the sum of its proper divisors (2640868617563).
13204343087785 is an equidigital number, since it uses as much as digits as its factorization.
13204343087785 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2640868617562.
The product of its (nonzero) digits is 13547520, while the sum is 55.
The spelling of 13204343087785 in words is "thirteen trillion, two hundred four billion, three hundred forty-three million, eighty-seven thousand, seven hundred eighty-five".
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