132044314231441 has 4 divisors (see below), whose sum is σ = 132045180685632. Its totient is φ = 132043447777252.

The previous prime is 132044314231439. The next prime is 132044314231447. The reversal of 132044314231441 is 144132413440231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132044314231441 - 2¹ = 132044314231439 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132044314231441.

It is not an unprimeable number, because it can be changed into a prime (132044314231447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 432998461 + ... + 433303306.

It is an arithmetic number, because the mean of its divisors is an integer number (33011295171408).

Almost surely, 2^{132044314231441} is an apocalyptic number.

It is an amenable number.

132044314231441 is a deficient number, since it is larger than the sum of its proper divisors (866454191).

132044314231441 is an equidigital number, since it uses as much as digits as its factorization.

132044314231441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 866454190.

The product of its (nonzero) digits is 110592, while the sum is 37.

Adding to 132044314231441 its reverse (144132413440231), we get a palindrome (276176727671672).

The spelling of 132044314231441 in words is "one hundred thirty-two trillion, forty-four billion, three hundred fourteen million, two hundred thirty-one thousand, four hundred forty-one".