Search a number
-
+
132044330400403 = 239552486738077
BaseRepresentation
bin11110000001011111110111…
…011010000111101010010011
3122022112022111102022210211111
4132001133313122013222103
5114301403242040303103
61144500154501154151
736545613413330431
oct3601376732075223
9568468442283744
10132044330400403
1139089760138a63
12129870ab0bb957
13588a95b0a35c5
142486da03b7d51
15103eb992e986d
hex7817f7687a93

132044330400403 has 4 divisors (see below), whose sum is σ = 132596817138720. Its totient is φ = 131491843662088.

The previous prime is 132044330400343. The next prime is 132044330400427. The reversal of 132044330400403 is 304004033440231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132044330400403 - 225 = 132044296845971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132044330400443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 276243368800 + ... + 276243369277.

It is an arithmetic number, because the mean of its divisors is an integer number (33149204284680).

Almost surely, 2132044330400403 is an apocalyptic number.

132044330400403 is a deficient number, since it is larger than the sum of its proper divisors (552486738317).

132044330400403 is an equidigital number, since it uses as much as digits as its factorization.

132044330400403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 552486738316.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 132044330400403 its reverse (304004033440231), we get a palindrome (436048363840634).

The spelling of 132044330400403 in words is "one hundred thirty-two trillion, forty-four billion, three hundred thirty million, four hundred thousand, four hundred three".

Divisors: 1 239 552486738077 132044330400403