Base | Representation |
---|---|
bin | 10011001101110100000… |
… | …101011011011101001001 |
3 | 11200020110002111101220101 |
4 | 103031310011123131021 |
5 | 133113342122240410 |
6 | 2450344104125401 |
7 | 164255166251650 |
oct | 23156405333511 |
9 | 4606402441811 |
10 | 1320502540105 |
11 | 46a027293011 |
12 | 193b09766861 |
13 | 976a4936388 |
14 | 47cac4c8197 |
15 | 24538d5bd3a |
hex | 1337415b749 |
1320502540105 has 8 divisors (see below), whose sum is σ = 1810974912192. Its totient is φ = 905487456048.
The previous prime is 1320502540103. The next prime is 1320502540109. The reversal of 1320502540105 is 5010452050231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1320502540105 - 21 = 1320502540103 is a prime.
It is a super-2 number, since 2×13205025401052 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1320502540103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18864321967 + ... + 18864322036.
It is an arithmetic number, because the mean of its divisors is an integer number (226371864024).
Almost surely, 21320502540105 is an apocalyptic number.
It is an amenable number.
1320502540105 is a deficient number, since it is larger than the sum of its proper divisors (490472372087).
1320502540105 is an equidigital number, since it uses as much as digits as its factorization.
1320502540105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37728644015.
The product of its (nonzero) digits is 6000, while the sum is 28.
Adding to 1320502540105 its reverse (5010452050231), we get a palindrome (6330954590336).
The spelling of 1320502540105 in words is "one trillion, three hundred twenty billion, five hundred two million, five hundred forty thousand, one hundred five".
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