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1320645720947 = 7712657234851
BaseRepresentation
bin10011001101111100100…
…111100111101101110011
311200020211001220202002112
4103031330213213231303
5133114140301032242
62450410221035535
7164261555260550
oct23157447475563
94606731822075
101320645720947
1146a0a0097993
12193b496b5bab
13976c84b8477
1447cc3519a27
15245466e0c82
hex1337c9e7b73

1320645720947 has 8 divisors (see below), whose sum is σ = 1530567274752. Its totient is φ = 1116038637000.

The previous prime is 1320645720943. The next prime is 1320645720959. The reversal of 1320645720947 is 7490275460231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1320645720947 - 22 = 1320645720943 is a prime.

It is a super-3 number, since 3×13206457209473 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320645720895 and 1320645720904.

It is not an unprimeable number, because it can be changed into a prime (1320645720943) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1328616929 + ... + 1328617922.

It is an arithmetic number, because the mean of its divisors is an integer number (191320909344).

Almost surely, 21320645720947 is an apocalyptic number.

1320645720947 is a deficient number, since it is larger than the sum of its proper divisors (209921553805).

1320645720947 is an equidigital number, since it uses as much as digits as its factorization.

1320645720947 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2657234929.

The product of its (nonzero) digits is 2540160, while the sum is 50.

The spelling of 1320645720947 in words is "one trillion, three hundred twenty billion, six hundred forty-five million, seven hundred twenty thousand, nine hundred forty-seven".

Divisors: 1 7 71 497 2657234851 18600643957 188663674421 1320645720947