13210011124403 has 4 divisors (see below), whose sum is σ = 13233474732648. Its totient is φ = 13186547516160.

The previous prime is 13210011124399. The next prime is 13210011124463. The reversal of 13210011124403 is 30442111001231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13210011124403 - 2² = 13210011124399 is a prime.

It is a super-4 number, since 4×13210011124403⁴ (a number of 54 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13210011124463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11731803278 + ... + 11731804403.

It is an arithmetic number, because the mean of its divisors is an integer number (3308368683162).

Almost surely, 2^{13210011124403} is an apocalyptic number.

13210011124403 is a deficient number, since it is larger than the sum of its proper divisors (23463608245).

13210011124403 is an equidigital number, since it uses as much as digits as its factorization.

13210011124403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23463608244.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13210011124403 its reverse (30442111001231), we get a palindrome (43652122125634).

The spelling of 13210011124403 in words is "thirteen trillion, two hundred ten billion, eleven million, one hundred twenty-four thousand, four hundred three".