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13210141051 = 27074879993
BaseRepresentation
bin11000100110110001…
…01100000101111011
31021002122012200210101
430103120230011323
5204023244003201
610022455100231
7645234226522
oct142330540573
937078180711
1013210141051
115669864548
122688071677
131326a99b13
148d462b4b9
15524b10d01
hex31362c17b

13210141051 has 4 divisors (see below), whose sum is σ = 13215023752. Its totient is φ = 13205258352.

The previous prime is 13210141027. The next prime is 13210141099. The reversal of 13210141051 is 15014101231.

13210141051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13210141051 - 29 = 13210140539 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13210741051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2437290 + ... + 2442703.

It is an arithmetic number, because the mean of its divisors is an integer number (3303755938).

Almost surely, 213210141051 is an apocalyptic number.

13210141051 is a deficient number, since it is larger than the sum of its proper divisors (4882701).

13210141051 is an equidigital number, since it uses as much as digits as its factorization.

13210141051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4882700.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 13210141051 its reverse (15014101231), we get a palindrome (28224242282).

The spelling of 13210141051 in words is "thirteen billion, two hundred ten million, one hundred forty-one thousand, fifty-one".

Divisors: 1 2707 4879993 13210141051