1321020313001 has 4 divisors (see below), whose sum is σ = 1330524056400. Its totient is φ = 1311516569604.

The previous prime is 1321020312923. The next prime is 1321020313013. The reversal of 1321020313001 is 1003130201231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1321020313001 is a prime.

It is a super-2 number, since 2×1321020313001² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1321020313021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4751871491 + ... + 4751871768.

It is an arithmetic number, because the mean of its divisors is an integer number (332631014100).

Almost surely, 2^{1321020313001} is an apocalyptic number.

It is an amenable number.

1321020313001 is a deficient number, since it is larger than the sum of its proper divisors (9503743399).

1321020313001 is an equidigital number, since it uses as much as digits as its factorization.

1321020313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9503743398.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1321020313001 its reverse (1003130201231), we get a palindrome (2324150514232).

The spelling of 1321020313001 in words is "one trillion, three hundred twenty-one billion, twenty million, three hundred thirteen thousand, one".