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132103002113 = 1274212470739
BaseRepresentation
bin111101100000111110…
…0111101100000000001
3110121222111002211011222
41323001330331200001
54131021332031423
6140404241444425
712354430663565
oct1730174754001
9417874084158
10132103002113
115102a778805
1221729040715
13c5c37a3c94
1465728d76a5
1536827c03c8
hex1ec1f3d801

132103002113 has 8 divisors (see below), whose sum is σ = 133459491840. Its totient is φ = 130751454960.

The previous prime is 132103002091. The next prime is 132103002121. The reversal of 132103002113 is 311200301231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132103002113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132103002091 and 132103002100.

It is not an unprimeable number, because it can be changed into a prime (132103002613) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1181903 + ... + 1288836.

It is an arithmetic number, because the mean of its divisors is an integer number (16682436480).

Almost surely, 2132103002113 is an apocalyptic number.

It is an amenable number.

132103002113 is a deficient number, since it is larger than the sum of its proper divisors (1356489727).

132103002113 is a wasteful number, since it uses less digits than its factorization.

132103002113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2471287.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 132103002113 its reverse (311200301231), we get a palindrome (443303303344).

The spelling of 132103002113 in words is "one hundred thirty-two billion, one hundred three million, two thousand, one hundred thirteen".

Divisors: 1 127 421 53467 2470739 313783853 1040181119 132103002113