Base | Representation |
---|---|
bin | 11110000010010111011100… |
… | …100101110010001001111011 |
3 | 122022202000112121001100220211 |
4 | 132002113130211302021323 |
5 | 114303343003030442410 |
6 | 1144543424442331551 |
7 | 36553125342564100 |
oct | 3602273445621173 |
9 | 568660477040824 |
10 | 132104010015355 |
11 | 39101aa5788a94 |
12 | 129967857b9bb7 |
13 | 589347c346231 |
14 | 2489c224acaa7 |
15 | 10414dd86368a |
hex | 7825dc97227b |
132104010015355 has 12 divisors (see below), whose sum is σ = 184406413980960. Its totient is φ = 90585606867504.
The previous prime is 132104010015319. The next prime is 132104010015359. The reversal of 132104010015355 is 553510010401231.
It is not a de Polignac number, because 132104010015355 - 211 = 132104010013307 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132104010015359) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 269600020195 + ... + 269600020684.
It is an arithmetic number, because the mean of its divisors is an integer number (15367201165080).
Almost surely, 2132104010015355 is an apocalyptic number.
132104010015355 is a deficient number, since it is larger than the sum of its proper divisors (52302403965605).
132104010015355 is an equidigital number, since it uses as much as digits as its factorization.
132104010015355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 539200040898 (or 539200040891 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 132104010015355 its reverse (553510010401231), we get a palindrome (685614020416586).
The spelling of 132104010015355 in words is "one hundred thirty-two trillion, one hundred four billion, ten million, fifteen thousand, three hundred fifty-five".
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