13210401301403 has 4 divisors (see below), whose sum is σ = 13210408573488. Its totient is φ = 13210394029320.

The previous prime is 13210401301249. The next prime is 13210401301417. The reversal of 13210401301403 is 30410310401231.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13210401301403 - 2¹⁴ = 13210401285019 is a prime.

It is a super-3 number, since 3×13210401301403³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13210401301423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1665050 + ... + 5403072.

It is an arithmetic number, because the mean of its divisors is an integer number (3302602143372).

Almost surely, 2^{13210401301403} is an apocalyptic number.

13210401301403 is a deficient number, since it is larger than the sum of its proper divisors (7272085).

13210401301403 is an equidigital number, since it uses as much as digits as its factorization.

13210401301403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7272084.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13210401301403 its reverse (30410310401231), we get a palindrome (43620711702634).

The spelling of 13210401301403 in words is "thirteen trillion, two hundred ten billion, four hundred one million, three hundred one thousand, four hundred three".