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132104051 = 314261421
BaseRepresentation
bin1111101111110…
…11111101110011
3100012120120200122
413313323331303
5232304312201
621035240455
73162603002
oct767737563
9305516618
10132104051
1168629802
12382a912b
13214a43a1
141378ac39
15b8e6e1b
hex7dfbf73

132104051 has 4 divisors (see below), whose sum is σ = 136365504. Its totient is φ = 127842600.

The previous prime is 132104033. The next prime is 132104053. The reversal of 132104051 is 150401231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132104051 - 218 = 131841907 is a prime.

It is a super-2 number, since 2×1321040512 = 34902960581221202, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132104053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2130680 + ... + 2130741.

It is an arithmetic number, because the mean of its divisors is an integer number (34091376).

Almost surely, 2132104051 is an apocalyptic number.

132104051 is a deficient number, since it is larger than the sum of its proper divisors (4261453).

132104051 is an equidigital number, since it uses as much as digits as its factorization.

132104051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4261452.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 132104051 is about 11493.6526396094. The cubic root of 132104051 is about 509.2980873296.

Adding to 132104051 its reverse (150401231), we get a palindrome (282505282).

The spelling of 132104051 in words is "one hundred thirty-two million, one hundred four thousand, fifty-one".

Divisors: 1 31 4261421 132104051