Base | Representation |
---|---|
bin | 11110000010010111110101… |
… | …001110000101011010110011 |
3 | 122022202001121101121000020120 |
4 | 132002113311032011122303 |
5 | 114303344324321430303 |
6 | 1144543533443141323 |
7 | 36553141521066621 |
oct | 3602276516053263 |
9 | 568661541530216 |
10 | 132104423233203 |
11 | 39102197a61743 |
12 | 12996880074843 |
13 | 5893516b34c35 |
14 | 2489c61314511 |
15 | 1041514c88553 |
hex | 7825f53856b3 |
132104423233203 has 4 divisors (see below), whose sum is σ = 176139230977608. Its totient is φ = 88069615488800.
The previous prime is 132104423233183. The next prime is 132104423233231. The reversal of 132104423233203 is 302332324401231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132104423233203 - 217 = 132104423102131 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132104423233253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22017403872198 + ... + 22017403872203.
It is an arithmetic number, because the mean of its divisors is an integer number (44034807744402).
Almost surely, 2132104423233203 is an apocalyptic number.
132104423233203 is a deficient number, since it is larger than the sum of its proper divisors (44034807744405).
132104423233203 is an equidigital number, since it uses as much as digits as its factorization.
132104423233203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44034807744404.
The product of its (nonzero) digits is 62208, while the sum is 33.
Adding to 132104423233203 its reverse (302332324401231), we get a palindrome (434436747634434).
The spelling of 132104423233203 in words is "one hundred thirty-two trillion, one hundred four billion, four hundred twenty-three million, two hundred thirty-three thousand, two hundred three".
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