Base | Representation |
---|---|
bin | 1100000000111110110011… |
… | …1111001100011110010011 |
3 | 1201202221220100000200002120 |
4 | 3000033230333030132103 |
5 | 3212422112102034324 |
6 | 44033014431545323 |
7 | 2532314622536364 |
oct | 300175477143623 |
9 | 51687810020076 |
10 | 13211000424339 |
11 | 4233832369583 |
12 | 159446938b243 |
13 | 74aa3b020103 |
14 | 3395b7087b6b |
15 | 17d9ad731179 |
hex | c03ecfcc793 |
13211000424339 has 8 divisors (see below), whose sum is σ = 17620006641600. Its totient is φ = 8804663911656.
The previous prime is 13211000424283. The next prime is 13211000424343. The reversal of 13211000424339 is 93342400011231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13211000424339 - 219 = 13210999900051 is a prime.
It is a super-3 number, since 3×132110004243393 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13211000424539) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 667414597 + ... + 667434390.
It is an arithmetic number, because the mean of its divisors is an integer number (2202500830200).
Almost surely, 213211000424339 is an apocalyptic number.
13211000424339 is a deficient number, since it is larger than the sum of its proper divisors (4409006217261).
13211000424339 is a wasteful number, since it uses less digits than its factorization.
13211000424339 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1334852289.
The product of its (nonzero) digits is 15552, while the sum is 33.
The spelling of 13211000424339 in words is "thirteen trillion, two hundred eleven billion, four hundred twenty-four thousand, three hundred thirty-nine".
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