132110113100201 has 4 divisors (see below), whose sum is σ = 139063276947600. Its totient is φ = 125156949252804.

The previous prime is 132110113100191. The next prime is 132110113100257. The reversal of 132110113100201 is 102001311011231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132110113100201 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132110113100201.

It is not an unprimeable number, because it can be changed into a prime (132110113109201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3476581923671 + ... + 3476581923708.

It is an arithmetic number, because the mean of its divisors is an integer number (34765819236900).

Almost surely, 2^{132110113100201} is an apocalyptic number.

It is an amenable number.

132110113100201 is a deficient number, since it is larger than the sum of its proper divisors (6953163847399).

132110113100201 is an equidigital number, since it uses as much as digits as its factorization.

132110113100201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6953163847398.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 132110113100201 its reverse (102001311011231), we get a palindrome (234111424111432).

It can be divided in two parts, 132110 and 113100201, that added together give a palindrome (113232311).

The spelling of 132110113100201 in words is "one hundred thirty-two trillion, one hundred ten billion, one hundred thirteen million, one hundred thousand, two hundred one".