Base | Representation |
---|---|
bin | 11110000010011101111101… |
… | …110101001010000011000011 |
3 | 122022202200121110000202210102 |
4 | 132002131331311022003003 |
5 | 114304001322044110301 |
6 | 1144550543223353015 |
7 | 36553463662651532 |
oct | 3602357565120303 |
9 | 568680543022712 |
10 | 132111010144451 |
11 | 39104a68110648 |
12 | 12997bb9bb276b |
13 | 5894026695b60 |
14 | 248a2c8060319 |
15 | 104179d1a5b6b |
hex | 78277dd4a0c3 |
132111010144451 has 8 divisors (see below), whose sum is σ = 143059436402064. Its totient is φ = 121274875438560.
The previous prime is 132111010144447. The next prime is 132111010144481. The reversal of 132111010144451 is 154441010111231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132111010144451 - 22 = 132111010144447 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132111010144481) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28072885481 + ... + 28072890186.
It is an arithmetic number, because the mean of its divisors is an integer number (17882429550258).
Almost surely, 2132111010144451 is an apocalyptic number.
132111010144451 is a deficient number, since it is larger than the sum of its proper divisors (10948426257613).
132111010144451 is a wasteful number, since it uses less digits than its factorization.
132111010144451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56145775861.
The product of its (nonzero) digits is 1920, while the sum is 29.
Adding to 132111010144451 its reverse (154441010111231), we get a palindrome (286552020255682).
The spelling of 132111010144451 in words is "one hundred thirty-two trillion, one hundred eleven billion, ten million, one hundred forty-four thousand, four hundred fifty-one".
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