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1321113113203 = 13101624085631
BaseRepresentation
bin10011001110011000011…
…110100101001001110011
311200022000122101201201211
4103032120132211021303
5133121114424110303
62450524434540551
7164306262115312
oct23163036451163
94608018351654
101321113113203
1146a30aa02684
1219405a137757
1397771294630
1447d29624279
152457276766d
hex133987a5273

1321113113203 has 4 divisors (see below), whose sum is σ = 1422737198848. Its totient is φ = 1219489027560.

The previous prime is 1321113113167. The next prime is 1321113113213. The reversal of 1321113113203 is 3023113111231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1321113113203 - 229 = 1320576242291 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1321113113213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50812042803 + ... + 50812042828.

It is an arithmetic number, because the mean of its divisors is an integer number (355684299712).

Almost surely, 21321113113203 is an apocalyptic number.

1321113113203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1321113113203 is a deficient number, since it is larger than the sum of its proper divisors (101624085645).

1321113113203 is a wasteful number, since it uses less digits than its factorization.

1321113113203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101624085644.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 1321113113203 its reverse (3023113111231), we get a palindrome (4344226224434).

The spelling of 1321113113203 in words is "one trillion, three hundred twenty-one billion, one hundred thirteen million, one hundred thirteen thousand, two hundred three".

Divisors: 1 13 101624085631 1321113113203