Base | Representation |
---|---|
bin | 10011001110011000111… |
… | …101000011100100101011 |
3 | 11200022001012102121110202 |
4 | 103032120331003210223 |
5 | 133121124000231443 |
6 | 2450525322102415 |
7 | 164306420040524 |
oct | 23163075034453 |
9 | 4608035377422 |
10 | 1321121102123 |
11 | 46a314469899 |
12 | 19406094aa0b |
13 | 97772b309c4 |
14 | 47d2a70384b |
15 | 245732e47b8 |
hex | 13398f4392b |
1321121102123 has 4 divisors (see below), whose sum is σ = 1351844848728. Its totient is φ = 1290397355520.
The previous prime is 1321121102111. The next prime is 1321121102129. The reversal of 1321121102123 is 3212011211231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1321121102123 - 24 = 1321121102107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1321121102095 and 1321121102104.
It is not an unprimeable number, because it can be changed into a prime (1321121102129) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15361873238 + ... + 15361873323.
It is an arithmetic number, because the mean of its divisors is an integer number (337961212182).
Almost surely, 21321121102123 is an apocalyptic number.
1321121102123 is a deficient number, since it is larger than the sum of its proper divisors (30723746605).
1321121102123 is an equidigital number, since it uses as much as digits as its factorization.
1321121102123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30723746604.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1321121102123 its reverse (3212011211231), we get a palindrome (4533132313354).
The spelling of 1321121102123 in words is "one trillion, three hundred twenty-one billion, one hundred twenty-one million, one hundred two thousand, one hundred twenty-three".
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