Base | Representation |
---|---|
bin | 1100000000111111111100… |
… | …0001110111000100101011 |
3 | 1201202222200102120211212211 |
4 | 3000033333001313010223 |
5 | 3212423222044104003 |
6 | 44033104443345551 |
7 | 2532325256414542 |
oct | 300177701670453 |
9 | 51688612524784 |
10 | 13211303113003 |
11 | 4233978209aa6 |
12 | 15945328222b7 |
13 | 74aa8894c928 |
14 | 33960535b159 |
15 | 17d9ca0c196d |
hex | c03ff07712b |
13211303113003 has 8 divisors (see below), whose sum is σ = 13215112067936. Its totient is φ = 13207494398400.
The previous prime is 13211303112949. The next prime is 13211303113027. The reversal of 13211303113003 is 30031130311231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13211303113003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13211303113093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 208872463 + ... + 208935703.
It is an arithmetic number, because the mean of its divisors is an integer number (1651889008492).
Almost surely, 213211303113003 is an apocalyptic number.
13211303113003 is a deficient number, since it is larger than the sum of its proper divisors (3808954933).
13211303113003 is an equidigital number, since it uses as much as digits as its factorization.
13211303113003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 120165.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 13211303113003 its reverse (30031130311231), we get a palindrome (43242433424234).
The spelling of 13211303113003 in words is "thirteen trillion, two hundred eleven billion, three hundred three million, one hundred thirteen thousand, three".
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