Base | Representation |
---|---|
bin | 11000100110111010… |
… | …00111110011011011 |
3 | 1021002201101201212101 |
4 | 30103131013303123 |
5 | 204024043200011 |
6 | 10022540024231 |
7 | 645250136515 |
oct | 142335076333 |
9 | 37081351771 |
10 | 13211303131 |
11 | 566a488644 |
12 | 2688532077 |
13 | 13270b5a40 |
14 | 8d4850bb5 |
15 | 524c902c1 |
hex | 313747cdb |
13211303131 has 8 divisors (see below), whose sum is σ = 14353466400. Its totient is φ = 12087126912.
The previous prime is 13211303123. The next prime is 13211303153. The reversal of 13211303131 is 13130311231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13211303131 - 23 = 13211303123 is a prime.
It is a super-2 number, since 2×132113031312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13211303099 and 13211303108.
It is not an unprimeable number, because it can be changed into a prime (13211403131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4495231 + ... + 4498168.
It is an arithmetic number, because the mean of its divisors is an integer number (1794183300).
Almost surely, 213211303131 is an apocalyptic number.
13211303131 is a deficient number, since it is larger than the sum of its proper divisors (1142163269).
13211303131 is a wasteful number, since it uses less digits than its factorization.
13211303131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8993525.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13211303131 its reverse (13130311231), we get a palindrome (26341614362).
The spelling of 13211303131 in words is "thirteen billion, two hundred eleven million, three hundred three thousand, one hundred thirty-one".
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