132113432400041 has 8 divisors (see below), whose sum is σ = 140617191988224. Its totient is φ = 123691048502080.

The previous prime is 132113432400013. The next prime is 132113432400071. The reversal of 132113432400041 is 140004234311231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132113432400041 is a prime.

It is a super-2 number, since 2×132113432400041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 132113432399977 and 132113432400013.

It is not an unprimeable number, because it can be changed into a prime (132113432400071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20343919205 + ... + 20343925698.

It is an arithmetic number, because the mean of its divisors is an integer number (17577148998528).

Almost surely, 2^{132113432400041} is an apocalyptic number.

It is an amenable number.

132113432400041 is a deficient number, since it is larger than the sum of its proper divisors (8503759588183).

132113432400041 is a wasteful number, since it uses less digits than its factorization.

132113432400041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40687845111.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 132113432400041 its reverse (140004234311231), we get a palindrome (272117666711272).

The spelling of 132113432400041 in words is "one hundred thirty-two trillion, one hundred thirteen billion, four hundred thirty-two million, four hundred thousand, forty-one".