Base | Representation |
---|---|
bin | 111101100001010100… |
… | …0000101000111101011 |
3 | 110122000021101002112111 |
4 | 1323002220011013223 |
5 | 4131032230234030 |
6 | 140405324023151 |
7 | 12354626032243 |
oct | 1730250050753 |
9 | 418007332474 |
10 | 132114305515 |
11 | 51036099165 |
12 | 21730991ab7 |
13 | c5c5c30b9a |
14 | 65741dab23 |
15 | 36837a462a |
hex | 1ec2a051eb |
132114305515 has 4 divisors (see below), whose sum is σ = 158537166624. Its totient is φ = 105691444408.
The previous prime is 132114305509. The next prime is 132114305581. The reversal of 132114305515 is 515503411231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 515503411231 = 1109 ⋅464836259.
It is a cyclic number.
It is not a de Polignac number, because 132114305515 - 29 = 132114305003 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13211430547 + ... + 13211430556.
It is an arithmetic number, because the mean of its divisors is an integer number (39634291656).
Almost surely, 2132114305515 is an apocalyptic number.
132114305515 is a deficient number, since it is larger than the sum of its proper divisors (26422861109).
132114305515 is an equidigital number, since it uses as much as digits as its factorization.
132114305515 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26422861108.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 132114305515 its reverse (515503411231), we get a palindrome (647617716746).
The spelling of 132114305515 in words is "one hundred thirty-two billion, one hundred fourteen million, three hundred five thousand, five hundred fifteen".
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