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132115012461235 = 544925295881543
BaseRepresentation
bin11110000010100001101100…
…011000110010001010110011
3122022210001221101002112021101
4132002201230120302022303
5114304033021142224420
61144552444315105231
736553665112044556
oct3602415430621263
9568701841075241
10132115012461235
1139106731337471
1212998936442217
135894513918c3b
14248a58781869d
15104193473760a
hex78286c6322b3

132115012461235 has 8 divisors (see below), whose sum is σ = 158538077197920. Its totient is φ = 105691968472704.

The previous prime is 132115012461197. The next prime is 132115012461241. The reversal of 132115012461235 is 532164210511231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132115012461235 - 213 = 132115012453043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132115012461194 and 132115012461203.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19521874 + ... + 25403416.

It is an arithmetic number, because the mean of its divisors is an integer number (19817259649740).

Almost surely, 2132115012461235 is an apocalyptic number.

132115012461235 is a deficient number, since it is larger than the sum of its proper divisors (26423064736685).

132115012461235 is an equidigital number, since it uses as much as digits as its factorization.

132115012461235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10374077.

The product of its (nonzero) digits is 43200, while the sum is 37.

Adding to 132115012461235 its reverse (532164210511231), we get a palindrome (664279222972466).

The spelling of 132115012461235 in words is "one hundred thirty-two trillion, one hundred fifteen billion, twelve million, four hundred sixty-one thousand, two hundred thirty-five".

Divisors: 1 5 4492529 5881543 22462645 29407715 26423002492247 132115012461235