Base | Representation |
---|---|
bin | 11110000010100110101000… |
… | …001010001000010101010001 |
3 | 122022210120121120202120020011 |
4 | 132002212220022020111101 |
5 | 114304124343404020423 |
6 | 1144555122124314521 |
7 | 36554243311205665 |
oct | 3602465012102521 |
9 | 568716546676204 |
10 | 132120310220113 |
11 | 391089aa828096 |
12 | 129999746a2a41 |
13 | 5894b7936c4c7 |
14 | 248a92b2688a5 |
15 | 1041b448a8b0d |
hex | 7829a8288551 |
132120310220113 has 8 divisors (see below), whose sum is σ = 132299821555200. Its totient is φ = 131940803432928.
The previous prime is 132120310220111. The next prime is 132120310220131. The reversal of 132120310220113 is 311022013021231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132120310220113 - 21 = 132120310220111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132120310220111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59175373 + ... + 61367461.
It is an arithmetic number, because the mean of its divisors is an integer number (16537477694400).
Almost surely, 2132120310220113 is an apocalyptic number.
It is an amenable number.
132120310220113 is a deficient number, since it is larger than the sum of its proper divisors (179511335087).
132120310220113 is an equidigital number, since it uses as much as digits as its factorization.
132120310220113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2273951.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 132120310220113 its reverse (311022013021231), we get a palindrome (443142323241344).
The spelling of 132120310220113 in words is "one hundred thirty-two trillion, one hundred twenty billion, three hundred ten million, two hundred twenty thousand, one hundred thirteen".
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