Base | Representation |
---|---|
bin | 11110000010100111010001… |
… | …010010101111100111001011 |
3 | 122022210122101200100111020112 |
4 | 132002213101102233213023 |
5 | 114304132302042002021 |
6 | 1144555314420144535 |
7 | 36554266361155010 |
oct | 3602472122574713 |
9 | 568718350314215 |
10 | 132121000344011 |
11 | 39109224341418 |
12 | 12999b2783814b |
13 | 5894c59331543 |
14 | 248a994b91707 |
15 | 1041b85279d5b |
hex | 7829d14af9cb |
132121000344011 has 8 divisors (see below), whose sum is σ = 151406860654080. Its totient is φ = 112937997956328.
The previous prime is 132121000344001. The next prime is 132121000344013. The reversal of 132121000344011 is 110443000121231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132121000344011 - 214 = 132121000327627 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132121000344013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25714477841 + ... + 25714482978.
It is an arithmetic number, because the mean of its divisors is an integer number (18925857581760).
Almost surely, 2132121000344011 is an apocalyptic number.
132121000344011 is a deficient number, since it is larger than the sum of its proper divisors (19285860310069).
132121000344011 is an equidigital number, since it uses as much as digits as its factorization.
132121000344011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51428961193.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 132121000344011 its reverse (110443000121231), we get a palindrome (242564000465242).
The spelling of 132121000344011 in words is "one hundred thirty-two trillion, one hundred twenty-one billion, three hundred forty-four thousand, eleven".
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