Base | Representation |
---|---|
bin | 11110000010101010010010… |
… | …100110000001011001111001 |
3 | 122022210221202200201211010220 |
4 | 132002222102212001121321 |
5 | 114304210422302302223 |
6 | 1145001012310130253 |
7 | 36554442630532443 |
oct | 3602522246013171 |
9 | 568727680654126 |
10 | 132124243400313 |
11 | 3910a638a2263a |
12 | 1299a691950989 |
13 | 5895355196a78 |
14 | 248abc1787493 |
15 | 1041cc4d306e3 |
hex | 782a92981679 |
132124243400313 has 8 divisors (see below), whose sum is σ = 176211738357888. Its totient is φ = 88059788688144.
The previous prime is 132124243400299. The next prime is 132124243400321. The reversal of 132124243400313 is 313004342421231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132124243400313 - 213 = 132124243392121 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132124243400323) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5760047970 + ... + 5760070907.
It is an arithmetic number, because the mean of its divisors is an integer number (22026467294736).
Almost surely, 2132124243400313 is an apocalyptic number.
It is an amenable number.
132124243400313 is a deficient number, since it is larger than the sum of its proper divisors (44087494957575).
132124243400313 is a wasteful number, since it uses less digits than its factorization.
132124243400313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11520122703.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 132124243400313 its reverse (313004342421231), we get a palindrome (445128585821544).
The spelling of 132124243400313 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, two hundred forty-three million, four hundred thousand, three hundred thirteen".
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